Can anyone solve this ultimate Physics problem? :angry: :-
(This post consists of superscripts and symbols which might won't be supported by any app like Tapatalk or WPC app!!)
A particle moves with initial velocity 'u' along x-axis with acceleration 'a' along negative x-axis. If 't' be the time at which the direction of motion changes and 'p' be the time such that p<t but (p+1)>t, then the distance covered in (p+1)[SUP]th[/SUP] second is:-
A.) u(p+1)+? a(p+1)[SUP]2[/SUP]-(u[SUP]2[/SUP]/2a)
B.) u(p+1)+? a(p+1)[SUP]2[/SUP]-up+?ap[SUP]2[/SUP]
C.) (u[SUP]2[/SUP]/2a)+? a(p+1-t)[SUP]2[/SUP]-up+?ap[SUP]2
[/SUP]
D.) (u[SUP]2[/SUP]/2a)+u(p+1-t)+? a(p+1-t)[SUP]2[/SUP]-up+?ap[SUP]2[/SUP]
Any Physics lover and pro over here?
Hint:- You have to use Kinematical Equations and some brain.